3x^2-32x+56=0

Solution for 3x^2-32x+56=0 equation:

3x^2-32x+56=0

a = 3; b = -32; c = +56;
Δ = b2-4ac
Δ = -322-4·3·56
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{22}}{2*3}=\frac{32-4\sqrt{22}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{22}}{2*3}=\frac{32+4\sqrt{22}}{6}
$